defining arrays of structure
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In order to increase the speed of processing, I am trying to define an array of structures before proceeding to my main code, say, 100×50 arrays of the same structure. How can I define it beforehand?
struct('dir1',{},'dir2',{},'x1',{},'x2',{},'x3',{},'x4',{})
is the following correct?
n1=100;
n2=50;
data{n1,n2}=struct('dir1',{},'dir2',{},'x1',{},'x2',{},'x3',{},'x4',{})
Thanks a lot for your quick reply :)
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Jan
2011 年 6 月 1 日
C = cell(100, 50);
S = struct('dir1', C, 'dir2', C ,'x1', C, 'x2', C, 'x3', C, 'x4', C);
Another method:
% S must be undefined before, otherwise use "clear('S')"
S(100, 50) = struct('dir1', [], 'dir2', [] ,'x1', [], ...
'x2', [], 'x3', [], 'x4', []);
7 件のコメント
Jan
2011 年 6 月 1 日
@Ahmad: The S(100, 50)=struct() is 3 times faster. But we are talking about 0.1e-3 sec. I assume that reading this message will waste more time than using the worse method.
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