How do you write a nested if statement that checks if the user has entered certain numbers?

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Akana Juliet
Akana Juliet 2021 年 6 月 21 日
コメント済み: Akana Juliet 2021 年 6 月 21 日
Hi all, I am trying to implement a way to check if a user has entered a certain number in an already nested if statement.
I am trying to have the user input a number, and if it falls under "badValues" array, then it either exits or goes back to beginning of program. Is there anyway this is possible? I have included the code here that is failing me.
I will shorten it because the other things are irrelevant, but it looks like:
if (modeSelected == 1)
badValues = [8 43 55];
correctRange = setdiff(0:100,badValues);
isRandom = input('Type 1 for random index or 2 for user selected index:\n');
if (isRandom == 1)
% Random function is here blah blah
elseif (isRandom == 2)
userSelected = input('Input index 0-100 except for 8 43 55:\n');
if (userSelected = badValues)
error('Input Error - input index 0-100 except for 8 43 55 )')
% userselected function is here blahblah
error('Input Error - enter 1 or 2')
Thank you in advance!


Scott MacKenzie
Scott MacKenzie 2021 年 6 月 21 日
This is an example of input validation. Here's one method that achieves what you are after. The prompt is repeated until the user enters a correct value.
while true
userSelected = input('Input index 0-100 except for 8 43 55: ');
if (~ismember(userSelected, badValues))
break; % input is OK, exit loop and proceed

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