How to print strings from a data text file that is in correlation to an indices text file?

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Akana Juliet
Akana Juliet 2021 年 6 月 15 日
編集済み: dpb 2021 年 6 月 16 日
Hi everyone, I was hoping someone could help me with this tricky concept. I am trying to write a program and I don't really know how to execute it. You will see in the text files I've attached, I have one called index.txt and that has an array from 0 - 7, each index has 4 array elements (looks like this 0 1 6 2 3 1 3 2 4 0 2 1 6 4 7 ..etc). Then in the data.txt file I have another array 0 - 7 but each index includes a hexidecimal value. There are 3 categories, it should make sense when you view the text files. I'm looking for this to happen:
1.) User selects a category (Category 1, 2, and 3)
2.) User can either select index from 0-7 or an index at random.
3.) The program prints 4 strings(since the indices each contain 4 numbers) from the data.txt that is correlated to index file.
I was thinking to read line by line searching for "First Index, Second Index or Third Index to accomplish #1, and then maybe put the strings in cell arrays. This is honestly really complex for me, so any pointers on how I can get started on this would be greatly appreciated!

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dpb
dpb 2021 年 6 月 15 日
編集済み: dpb 2021 年 6 月 16 日
Put the indices into a 3D array and just index --
indices(:,:,1)=[1 6 2 3; 3 2 4 0; 1 6 4 7; 0 1 4 7; ...
0 5 6 1; 0 1 2 3; 0 5 6 2; 0 3 6 7];
indices(:,:,2)=[
0 6 2 3; 3 2 4 0; 1 6 4 7; 0 1 4 7; ...
0 5 6 1; 0 7 2 3; 0 5 6 2; 0 5 6 7]; % NB: presumed the last 4 0 5 6 7 ==>7 0 5 6 7 fixed typo
indices(:,:,3)=[
4 6 2 3; 3 2 4 0; 1 6 2 7; 0 1 4 7; ...
5 0 6 1; 0 1 2 3; 0 5 6 2; 0 5 6 0];
Do same thing with DATA array, then
icat=input('Enter category (1-3)'); % get the category
indx=input('Enter index (1-8)'); % and index (in MATLAB 1-based counting)
output=data(indices(indx,:,icat)); % retrieve data from icat plane, index row of lookup indices
  6 件のコメント
dpb
dpb 2021 年 6 月 16 日
To show they're the same, I copied the code above for plane 1 to command line as I1 and
>> I1=[1 6 2 3; 3 2 4 0; 1 6 4 7; 0 1 4 7; ...
>> all(I1==indices(:,:,1),'all') % they aren't the same as is, agreed...
ans =
logical
0
>> all(I1==indices(:,:,1)-1,'all') % but they are the same when take off the "1"
ans =
logical
1
>>

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