Conditionals in argument blocks

9 ビュー (過去 30 日間)
Roy Goodman
Roy Goodman 2021 年 5 月 31 日
コメント済み: Roy Goodman 2021 年 6 月 9 日
Is it possible to make the default value of one optional variable depend on the value of another optional variable?
In particular suppose I define a function with required argument shape and optional argument v1 so that when. The variable shape can take one of two names, and the variable v1 has different default values depending on the value of shape, or else can be specificed by a name value pair.
I should be able to make the calls
myFunction('rectangle')
and the arguments block should assign v1=[1 0].
If I make the call
myFunction('triangle')
and the arguments block should assign v1=[1 sqrt(3)]/2
But then I should be able to override the defaults with the calls
myfunction('rectangle',v1=[6 4])
or else
myfunction('rectangle',v1=[5 21])
and opts.v1 will take the value specified

回答 (1 件)

Chidvi Modala
Chidvi Modala 2021 年 6 月 8 日
You may refer to the following piece of code
function v1 = myfunction(shape, varargin)
if strcmp(shape,'rectangle')
if nargin >1
v1 = varargin{1};
else
v1=[1 0];
end
elseif strcmp(shape,'triangle')
if nargin >1
v1 = varargin{1};
else
v1=[1 sqrt(3)]/2;
end
end
end
  3 件のコメント
Roy Goodman
Roy Goodman 2021 年 6 月 9 日
Thanks for your response. I read the documentation first and then saw no way to acccomplish what I'm trying to do. That's why I posted a question.

サインインしてコメントする。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by