Given a linear system i want to do Gauss-Seidel iteration.But getting error.Would appreciate if anyone fix me the code. Thanks.

>> x(1)=1.5;

>> y(1)=-1;

>> z(1)=1;

>> iter(1)=0;

>> for n=1:4

iter(n+1)=n;

x(n+1)=(16+3*y(n)-2*z(n))/8;

y(n+1)=(-9+2*x(n+1)-z(n))/8;

z(n+1)=(1+2*x(n+1)-4*y(n+1))/10;

end

>> Solution = [iter',x',y',z’]

Answer 1

[KALYAN ACHARJYA]

No coding syntax error

x(1)=1.5;
y(1)=-1;
z(1)=1;
iter(1)=0;
for n=1:4
 iter(n+1)=n;   
 x(n+1)=(16+3*y(n)-2*z(n))/8;
 y(n+1)=(-9+2*x(n+1)-z(n))/8;
 z(n+1)=(1+2*x(n+1)-4*y(n+1))/10;
end
Solution = [iter',x',y',z']

Result:

Solution =
            0          1.5           -1            1
            1        1.375     -0.90625       0.7375
            2       1.4758     -0.84824      0.73445
            3       1.4983     -0.84223      0.73655
            4          1.5     -0.84206      0.73683

[Abid Shahriar]

I am trying it on mobile version and i am getting different errors.

[Abid Shahriar]

like this with your executed code

[KALYAN ACHARJYA]

Can you delete the z' (transpose sign) & type it again?

Note on the z' (superscript sign)