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find the row and column value of a specific value in cell array

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Elysi Cochin
Elysi Cochin 2021 年 4 月 13 日
コメント済み: Rik 2021 年 4 月 13 日
i have a cell array with values
cellarr = {'a','b','c',3,5;'b',5,'a',[],[];'a','c',3,'a',4;'b','a','c','c',3};
i wanted to find the location where a particular number or string occurs
for example i want to get the location where the number = 3
so my expected output is
1st row 3rd column
3rd row 3rd column
4th row 5th column
[row,col] = find(___)
i want both the row and column position as it comes for find function
find not working with cell array
  3 件のコメント
Xingwang Yong
Xingwang Yong 2021 年 4 月 13 日
After using find(), you just need to convert the linear index into row and col index, see ind2sub

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Rik
Rik 2021 年 4 月 13 日
You need to use a bit of trickery to use find (ismember will not work normally either).
cellarr = {...
'a','b','c', 3 ,5;...
'b', 5 ,'a',[] ,[];...
'a','c', 3 ,'a',4;...
'b','a','c','c',3};
val=3;
[row,col] = find(cellfun(@(x) isequal(val,x),cellarr));
[row,col]
ans = 3×2
3 3 1 4 4 5
  2 件のコメント
Rik
Rik 2021 年 4 月 13 日
This is the default order for find, but you can use sort (and its second output) to sort on row instead of column.

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