Is there a way to call a part of a function using an index?
10 ビュー (過去 30 日間)
古いコメントを表示
I have a function that I call several times:
plot(position6(1),position6(2),'r+', 'MarkerSize', 100, 'Color', 'w');
h = images.roi.Circle(gca,'Center', position6,'Radius',100, 'Color', 'w', 'FaceAlpha', 0);
Where "position6" is one of N positions defined. Currently, I am manually defining each of them and writing these two lines of code for each position vector (which is in a matrix of vectors). Is there any way to condense this to make it neater, such that I can refer to each instance of the code using the index of the vector matrix? Perhaps with a function?
For example:
myfunc(6)
returns:
plot(position6(1),position6(2),'r+', 'MarkerSize', 100, 'Color', 'w');
h = images.roi.Circle(gca,'Center', position6,'Radius',100, 'Color', 'w', 'FaceAlpha', 0);
Thanks. Here's the full verson of the relevant code segment.
[rows, columns, numberOfColorChannels] = size(img);
figure;
imshow(img);
position1 = [(columns*0.75), (rows*0.5)];
position8 = [(columns*0.75), (rows*0.25)];
position9 = [(columns*0.75), (rows*0.75)];
position2 = [(columns*0.25), (rows*0.5)];
position6 = [(columns*0.25), (rows*0.25)];
position7 = [(columns*0.25), (rows*0.75)];
position3 = [(columns*0.5), (rows*0.5)];
position4 = [(columns*0.5), (rows*0.25)];
position5 = [(columns*0.5), (rows*0.75)];
position = {position1, position2, position3, position4, position5, position6, position7, position8, position9};
hold on;
plot(position{6}(1),position{6}(2),'r+', 'MarkerSize', 100, 'Color', 'w');
h = images.roi.Circle(gca,'Center', position{6},'Radius',100, 'Color', 'w', 'FaceAlpha', 0);
4 件のコメント
Jan
2021 年 3 月 23 日
@Teshan Rezel: We usually do not delete questions, if they got an answer already. Simply insert a link to the new question by editing the text of your question and mark it by: "[EDITED, better version of the question: ... ] "
採用された回答
Rik
2021 年 3 月 23 日
Reposting as answer:
For the reasons set out in the answer by Steven (and the subsequent comments), numbering your variables in not ideal. If you use arrays, you can index them:
columns = 80;
rows = 24;
[c,r]=ndgrid([0.75 0.25 0.5],[0.5 0.25 0.75]);
position=[columns*c(:) rows*r(:)];
position=mat2cell(position,ones(1,size(position,1)),2);
disp(position.')
myfun(position{6})
function h=myfunc(pos)
plot(pos(1),pos(2),'r+', 'MarkerSize', 100, 'Color', 'w');
h = images.roi.Circle(gca,'Center', pos,'Radius',100, 'Color', 'w', 'FaceAlpha', 0);
if nargout==0,clear,end
end
0 件のコメント
その他の回答 (1 件)
Steven Lord
2021 年 3 月 22 日
Do you mean you want to plot position6(1) versus position6(2) in the first call, position6(3) versus position6(4) in the second, etc.? That's easy, a simple for loop (incrementing by two) would be easiest.
for k = 1:2:10
fprintf("Processing elements %d and %d.\n", k, k+1)
end
Or do you want to plot position6(1) versus position6(2) in the first call, position7(1) versus position7(2) in the second, position8(1) versus position8(2) in the third, etc.?
13 件のコメント
Rik
2021 年 3 月 23 日
This sounds as simple as:
myfun(position{6})
function h=myfunc(pos)
plot(pos(1),pos(2),'r+', 'MarkerSize', 100, 'Color', 'w');
h = images.roi.Circle(gca,'Center', pos,'Radius',100, 'Color', 'w', 'FaceAlpha', 0);
if nargout==0,clear,end
end
Or am I misunderstanding what it is you want?
参考
カテゴリ
Help Center および File Exchange で Shifting and Sorting Matrices についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!