How to graph discrete equation: y(n) = y(n-1) + 1 for 1000 samples

I need to graph this equation, and I have no idea how to, because as soon as I declare y(n) = y(n-1) + 1, it throws results until 1000+ not having any regards of the n value.

Code used:

      n = 1;
      x = [];
      y (1) = 1;
      while n <= 1000;
                n = n+1;
                x = [n,y];
                y(n) = y(n-1) + 1;

      end
      stem(x);

[Rik]

You don't provide any details of what you did, so the only possible answer is this: write your code differently.

Have a read here and here. It will greatly improve your chances of getting an answer.

[Laura Rosas]

I tried to update it, I included the code I’m using, the only info I was given, was that y=1 when n = 1 and was told to graph y(n) = y(n-1) + 1

I’m sorry, I’m really new at matlab

Answer 1

[Rik]

I would do something like this:

%create a vector of the correct size
y=NaN(1000,1); % by using NaN we should notice it if we skip a value
y(1) = 1;
for n=2:numel(y)
    y(n)=y(n-1)+1;
end
%now we have a vector we can plot:
plot(y,'*')

In this case we could have taken a shortcut:

y=ones(1000,1);
y=cumsum(y);
plot(y,'*')

[Laura Rosas]

Thank you very much! It worked :)