Jacobi method in Matlab

4 ビュー (過去 30 日間)
gracias claude
gracias claude 2021 年 2 月 27 日
コメント済み: Walter Roberson 2021 年 2 月 27 日
My jacobi method not working. I feel like I'm missing something. Currently my numbers that are result back are m = 1 and be = 1.6. I wonder if I'm breaking out of one of the loops to fast
How to run :
n=100
[a,b]=sparsesetup(100);
[m,be] = Jacobi(a,b,0.00000025)
should result with -- getting wrong values
m = 36
be = 4.5785 * 10^-7
function [m,be] = Jacobi(a,b,tol)
n = length(b)
d= diag(a); % extract diagonal of a[i,j]
r=a-diag(d);
x=zeros(n,1);
p=zeros(n,1)
c=zeros([n,1]);
e=zeros([n,1]);
n1 =0;
err =0;
relerr = 1;
while(1)
x=b(b-r*x) ./d;
err =abs(norm(x-p));
relerr = err/(norm(x) + eps);
p=x;
n1= n1+1
if(err)
break
end
end
xc=x;
m=n1;
for i=1 : n
for j=1 : n
xa(j) = 1;
c(i) = c(i) + a(i,j) * xa(j);
e(i) = e(i) + a(i,j) * xc(j);
end
end
for i =1 : n
dif(i) = abs(xa(i) - xc(i));
dif2(i) = abs(e(i) - c(i));
end
fe = max (dif, [], 2);
be = max(dif2, [],2);
end
// sparesetup method
function [a,b] = sparsesetup (n)
e = ones(n,1);
a= spdiags ([-e 3*e -e], -1:1, n,n); %Entries of a{i,j}
b = zeros (n,1); % Entries of rhs b
b(1) = 2;
b(n) = 2;
b(2:n-1)=1;
end
  3 件のコメント
gracias claude
gracias claude 2021 年 2 月 27 日
I'm not sure what the threshold should be ?
Walter Roberson
Walter Roberson 2021 年 2 月 27 日
x=b(b-r*x) ./d;
That is indexing. Is it possible that you want multiplication instead of indexing?

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeMathematics についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by