How to add any number of variables together in all combinations?

I am trying to solve the three sum problem. It states that when provided a vector of a given length, three of the numbers in the vector add to zero. I am tasked with finding any and all of the combinations of numbers that add to zero.
For example, if the vector input is [3 1 3 -4 -6], the answers the code should output are: [3 1 -4], [3 1 -4] (repeated because two 3s are given) and [3 3 -6].
As of right now, I have code that assigns a variable to each of the numbers in the matrix:
---------------------------------
F = [3 1 3 -4 -6 ]; H = size(F); G = H(1,2);
for n = 1:G eval(['k' num2str(n) '= F(n)']) end
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What I need to do now is find out how to sum every combination of three of the numbers. If anyone could help me with this I'd be very grateful! Thank you for your time!

回答 (2 件)

Cedric
Cedric 2013 年 4 月 25 日
編集済み: Cedric 2013 年 4 月 25 日

1 投票

You can use NCHOOSEK. You should avoid using EVAL actually, which is quite slow, and rarely appropriate. Also, look at the doc of SUM and see how you can specify the dimension along which it has to perform the summation; this should be useful to you.

2 件のコメント

Mark Schillinger
Mark Schillinger 2013 年 4 月 25 日
I appreciate your quick response. I should have mentioned in my original post that I want to avoid using the nchoosek function all together. I know this is inefficient and makes the process much longer and more difficult.
Cedric
Cedric 2013 年 4 月 25 日
編集済み: Cedric 2013 年 4 月 25 日
Can you use RANDPERM or PERMS?
If not, there would be a not-that-simple solution based on BSXFUN I guess, but if the statement of your HW disallows this kind of functions, you might end up implementing a triple FOR loop, or a double FOR and and a FIND.
If you end up implementing a solution based on loops, "think on paper" and once you have an algorithm implement it (don't start thinking "what command should I type).
The triple FOR loop, for example, would be based on an approach where you sum up elements 1, 2, 3 of F (whose values are 3, 1, 3) in a first step and check whether the sum is null, then you sum up elements 1,2,4 and perform the same test, then 1,2,5, etc.
On this note, I'm off for the night!

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