Selection of row from a matrix

1 回表示 (過去 30 日間)
raj singh
raj singh 2013 年 4 月 20 日
i have a matrix,and i want remove that row in which numbers repeated
A= [3 5 5
6 9 1
7 5 7
2 4 6];
Ans: A=[6 9 1;2 4 6]
i used "for loop" for this problem, i want to ask there is any direct command to find the Ans. pls give me the suggestion.....

採用された回答

per isakson
per isakson 2013 年 4 月 20 日
Post the question at Cody:). It's a little exercise with logicl indexing.
>> A( any( diff( sort( A, 2 ), 1, 2 ) == 0, 2 ), : ) = []
A =
6 9 1
2 4 6
>>
  4 件のコメント
per isakson
per isakson 2013 年 4 月 20 日
Works here
A= [1 1 1 2
1 2 3 4
1 2 4 5
3 4 3 3];
A( any( diff( sort( A, 2 ), 1, 2 ) == 0, 2 ), : ) = []
A =
1 2 3 4
1 2 4 5
>>
raj singh
raj singh 2013 年 4 月 20 日
:) yaa, its working, it was my fault. thanks

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by