How to sort one array based on the order of a second array?
1 ビュー (過去 30 日間)
表示 古いコメント
Hi,
This seems like a very simple problem, but I can't seem to get it to work with the answers already available.
I have 2 string arrays:
A=["1a","1b","1c","1d","1e","2a","2b","2c","2d","2e"];
B=["A1_2a","U1_1c","Z1_2d","I1_1e","T1_1a","F1_2b","O1_1d","P1_2c","J1_2e","S1_1b"];
Let's say A is a newly sorted array from a previously disordered array (e.g. Q=["1c","2a","1e","2d","1b","2c","2e","1a","2b","1d"];)
How do I sort B, based on how Q was sorted?
The goal is to produce the array below
C=["T1_1a","S1_1b","U1_1c","O1_1d","I1_1e","A1_2a","F1_2b","P1_2c","Z1_2d","J1_2e"];
Thanks in advance.
0 件のコメント
採用された回答
Stephen23
2021 年 1 月 22 日
As far as I can tell, the order of Q is irrelevant.
A = ["1a","1b","1c","1d","1e","2a","2b","2c","2d","2e"]; % sorted
B = ["A1_2a","U1_1c","Z1_2d","I1_1e","T1_1a","F1_2b","O1_1d","P1_2c","J1_2e","S1_1b"];
[~,X] = ismember(A,extractAfter(B,'_'));
C = B(X)
その他の回答 (0 件)
参考
カテゴリ
Find more on Shifting and Sorting Matrices in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!