Easy Noob Indexing Question

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Richard Keniuk
Richard Keniuk 2020 年 12 月 19 日
コメント済み: Richard Keniuk 2020 年 12 月 27 日
I'm sure this answer is looming in front of me but I am missing it somehow. I have an array
A = [0 0;1 -1; -1 1;1 -1; -1 1];
and
B = [2 -2; -2 2;2 -2; -2 2;2 -2; -2 2;2 -2;0 0];
and I'm concatenating these two in the vertical direction but I only want rows 4:7 of my concatenated output.
I am doing this in two steps.
C = cat(1,A,B); % or some other calculation of vectors A and B
C = C(4:7,:);
How can I reduce this to one command by directly indexing the equation of "cat(1,A,B)" directly into C?
I know that I could do this by C = cat(1,A(end-1:end,:),B(1:2,:)). A and B are of variable length and I only want C to hold the concatenation +/-2 indices vertically. Is there another way in a single line?
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KALYAN ACHARJYA
KALYAN ACHARJYA 2020 年 12 月 19 日
Is there any issue with that, simplest and easiest?
C=[A;B];
C=C(4:7,:)
Image Analyst
Image Analyst 2020 年 12 月 19 日
My programs have thousands of lines of code. Why does yours have to be just one line of code instead of 2? Your last way of using end will work for variable sizes arrays.

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Rishabh Mishra
Rishabh Mishra 2020 年 12 月 23 日
Hi,
Use the code below for resolving your issue:
C=[A;B];
C=C(4:7,:);
This is the simplest way to code the solution for the issue you are facing.
Hope this helps !
  1 件のコメント
Richard Keniuk
Richard Keniuk 2020 年 12 月 27 日
I guess I already had this to the "cleanest" implementation. I thought maybe I was missing something here.
Thanks for your help.

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