Fliping a value between zero and one
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When p=0;
I have to use a loop to flip the value of p between 0 and 1 and each time it has to be different in a single line of code.
Thank you
2 件のコメント
Image Analyst
2013 年 2 月 15 日
What does the "When p=0;" mean? You only have to flip when p=0???
When you say "flip the value of p between 0 and 1" does that mean that p is either 0 or 1 only, or does it mean p can have a value between 0 and 1, like p=.426973 and flipping means inverting like flipped_p = 1-p?
採用された回答
Image Analyst
2013 年 2 月 15 日
Is this what you're looking for?
p=0;
for k = 1 : 5 % Here's the iterative loop it requested
clc;
% Here's the single line
p = ~p
pause(1);
end
fprintf('Done with demo!\n');
3 件のコメント
Image Analyst
2013 年 2 月 15 日
That also works for any value or p in between 0 and 1, like I asked about in my comment way up at the top. So perhaps this is the most general solution.
その他の回答 (2 件)
Youssef Khmou
2013 年 2 月 14 日
編集済み: Youssef Khmou
2013 年 2 月 14 日
your_vector=mod(0:1000,2); % single line code
for i=1:length(your_vector)
% YOUR CODE
fprintf('%d\n',your_vector(i))
pause(0.3)
end
0 件のコメント
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