How to calculate flotating point

  63.8061 +27.4180i
  50.1898 -11.8751i
  56.0887 +18.1713i
  50.1898 -11.8751i
  63.8061 +27.4180i

How can i convert this to

 63.81 +27.42i
  50.19 -11.87i
  56.09 +18.17i
  50.19 -11.87i
  63.81 +27.42i

that in math lab code

[madhan ravi]

Didn’t you ask this question on June 20th 2020??

Answer 1

[Walter Roberson]

Supposing that the data is stored in F, then

char(compose("%.2f %+.2f", round(real(F),2), round(imag(F),2)))

This will produce an output for display purposes. The internal versions of the data is not in character form and is not in base 10, so round(F,2) will only be values close to being the same as 2 decimal digits.

[madhab dhali]

Undefined function 'compose' for input arguments of type 'char'.

char(compose('%.2f %+.2f', round(real(Z_d),2), round(imag(Z_d),2)))

[John D'Errico]

compose was introduced in R2016b. So if your release is older, you will not be able to use it.

[Walter Roberson]

And if that is the case then we need to know which release you are using as that feature of round() might not have existed yet in your release.

[Walter Roberson]

Round2 = @(v) round(v,2);
char(strcat(sprintfc('%.2f', Round2(real(F(:)))), sprintfc(' %+.2f', Round2(imag(F(:))))))

Reminder: this is for presentation purposes. There is no way in MATLAB to round decimal values to store exactly 1/100ths, because MATLAB uses the IEEE 754 Binary Double Precision Floating Point standard, which does not represent values in decimal.

If you are using a version of MATLAB too old to support rounding to a particular number of decimal points, then

Round2 = @(v) round(v*100)/100;