A problem with transpose of a symbolic matrix
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Hi,
I don't understand the reason why if I have a matrix of symbolic like
Y =
[ 0, k]
[ 0, 0]
[ 0, 0]
If I try
Y'
it returns
ans =
[ 0, 0, 0]
[ conj(k), 0, 0]
How can I transpose as
Y' = [0 0 0; k 0 0] ?
0 件のコメント
採用された回答
Walter Roberson
2012 年 12 月 17 日
y' is not the transpose of y. y' is the conjugate transpose of y. If you want the plain transpose, use that appropriate operator, .'
y.'
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