How to find the location of a minimum value in cell array?
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consider the following example, Suppose if I have a cell notation
q=cell(5,1);
And if I have different dimensions for each cell, for example
q{1} = [6 7 9 4 0 0 1 2 3 1];
q{2} = [3 5 0 4 0 0 1 2 8 1];
q{3} = [3 5 0 5 4 3 4 2 6 4 0 0 1 2 8 1];
q{4} = [4 0 0 1 2 8 1];
q{5} = [4 0 0 0 2 8];
Now if I wish to find the latest cell location containing minimum non zero value, How can I find it?
In the above example, minimum non zero value is 1 and it is present in all cells, that is, q{1} q{2} q{3} q{4} except q{5}. So here the latest cell containing 1 is q{4} and 1 is located at 4th and 7th place of q{4}. I wish to get the location details mentioning that value 1 is present in q(4,4) and q(4,7). How can I find that?
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採用された回答
Matt Fig
2012 年 11 月 28 日
L = cellfun(@(x) find(x==1),q,'Un',0);
Now L has all the information you need.
14 件のコメント
nadia nadi
2015 年 8 月 26 日
Dear,
if I want to find minimum matrix from this code what should I do. I tried your code but I couldn't fit it to my code. I have many matrices when I want to find the maximum one by using the size I get the right answer but for minimum matrix I got empty matrix. I used this code
for i=1:10
MaxSubmat=load('MaxSubmatfile.txt');
Remind=load('Remindfile.txt');
ee{i}=MaxSubmat;
aa{i}=Remind;
end
[SizeMaxSubmat,MaxSubmat1]=max(cellfun(@(x) size(x,2),ee ))
[SizeRemind, Remind1]=min(cellfun(@(x) size(x,2),aa ))
MaxSub=ee{MaxSubmat1};
Reminder=aa{Remind1};
sizeReminder=size(Reminder,2)
I don't why it give give Reminder=[] and sizeReminder= 0 for while I know is more than one. could you please help me with this code I will appreciate that a lot.
regards, Nadia
Walter Roberson
2015 年 8 月 26 日
You are load()'ing the same file each time, and it has no data in it.
その他の回答 (1 件)
Vishal Rane
2012 年 11 月 28 日
The first thing that comes to mind is
find(q{n} > 0)
It will you give you locations of elements matching the condition ' > 0' in q{n}, else it returns empty.
You could use that to build your logic.
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