Subtract mean from each table by columns

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wbadry
wbadry 2020 年 6 月 14 日
コメント済み: Image Analyst 2020 年 6 月 22 日
Hello,
Assume we have the following table
t = array2table([rand(10,1),rand(10,1),rand(10,1)],'VariableNames',{'feat_1', 'feat_2','feat_3'});
t =
10×3 table
feat_1 feat_2 feat_3
________ ________ _________
0.12991 0.60198 0.82582
0.56882 0.26297 0.53834
0.46939 0.65408 0.99613
0.011902 0.68921 0.078176
0.33712 0.74815 0.44268
0.16218 0.45054 0.10665
0.79428 0.083821 0.9619
0.31122 0.22898 0.0046342
0.52853 0.91334 0.77491
0.16565 0.15238 0.8173
I can get the mean and standard deviation for each solumn using
meanArray = mean(table2array(t,1));
stdArray = std(table2array(t,1));
meanArray =
0.3479 0.4785 0.5547
stdArray =
0.2415 0.2836 0.3793
Is there any vector way to caclulate (element - mean / std) on every element in table without loop and keep the table? Thanks
I know normalize could standardize data but I need to make it in code.
  1 件のコメント
madhan ravi
madhan ravi 2020 年 6 月 14 日
Expected output?

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採用された回答

Image Analyst
Image Analyst 2020 年 6 月 14 日
編集済み: Image Analyst 2020 年 6 月 14 日
Try this:
t = array2table([rand(10,1),rand(10,1),rand(10,1)],'VariableNames',{'feat_1', 'feat_2','feat_3'})
m = table2array(t);
meanArray = mean(m)
stdArray = std(m)
z = (m - meanArray) ./ stdArray % a matrix
zt = array2table(z, 'VariableNames',{'feat_1', 'feat_2','feat_3'}) % a table
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wbadry
wbadry 2020 年 6 月 16 日
Thank you so much.

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その他の回答 (1 件)

wbadry
wbadry 2020 年 6 月 22 日
Hello,
I came by another solution using bsxfun
Here is a complete example based on my question
% Generate random columns for the example (10 by 3)
t = array2table([rand(10,1),rand(10,1),rand(10,1)],'VariableNames',...
{'feat_1', 'feat_2','feat_3'});
% Subtract from the mean vector (3 by 1)
t1 = bsxfun(@minus, mean(table2array(t)),table2array(t));
% Divide by stadard deviation vector (3 by 1) using right array division
t2 = bsxfun(@rdivide,t1,std(table2array(t)));
% Create the standardized table
t = array2table(t2,'VariableNames',{'feat_1', 'feat_2','feat_3'});
% Check mean and std of feat_1
feat_1_mu = mean(t.feat_1)
feat_1_sig = std(t.feat_1)
feat_1_mu =
0
feat_1_sig =
1
  1 件のコメント
Image Analyst
Image Analyst 2020 年 6 月 22 日
Yeah, you can do it that way if you want. I always find their *xfun() functions very cryptic and confusing than the regular math symbols. Plus you always have to find or figure out what the operations are. I mean, who would know, off the top of their head, that if you want to divide something you use @rdivide instead of the slash symbol /, or @minus instead of -. And it gets even more confusing for other operations.

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