Find column position of trues in a binary matrix
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Hello,
I have a binary matrix with with a large number of rows (~10^6) and small number of colums (~10) where the number of trues in each row is fixed.
I would like to obtain a matrix that for each row I have the column position of the trues.
For example:
I have the following binary matrix
A = [1 0 1 0 0;...
0 0 1 0 1;
...
...
1 1 0 0 0];
and I would like to obtain
c = [1 3;...
3 5;...
...
...
1 2];
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採用された回答
Fangjun Jiang
2020 年 3 月 19 日
編集済み: Fangjun Jiang
2020 年 3 月 19 日
see if you can get it from [i,j]=find(A)
>> A = [1 0 1 0 0;
0 0 1 0 1;
1 1 0 0 0];
[R,~]=find(A.');
out=transpose(reshape(R,2,[]))
out =
1 3
3 5
1 2
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