for loop. finding the right index

1 回表示 (過去 30 日間)
Ireedui Ganzorig
Ireedui Ganzorig 2020 年 3 月 18 日
コメント済み: Ireedui Ganzorig 2020 年 3 月 18 日
Hello MATLAB community,
stateOfEnergy is a bunch of data in a column, and I found the largest increase and decrease of stateOfEnergy by utilizing the for loop and built-in <max> and <min>. But I am really struggling to find indices where the largest increase and decrease occured. Below is my code. Is therer any way you can find that specific indices?
stateOfEnergy = load('40815SOE.csv'); % in kiloWattHour
for i = 2 : length(stateOfEnergy)
changeInSOE(i-1) = stateOfEnergy(i) - stateOfEnergy(i-1);
end
largestIncrease = max(changeInSOE); % largest increase of change in SOE in invertal of a single minute. in kWh
disp(['The Largest Increase in SOE was ', num2str(largestIncrease), 'kWh was found between index', ])
largestDecrease = min(changeInSOE); % % largest decrease of change in SOE in invertal of a single minute. in kWh
disp(['The Largest Decrease in SOE was ', num2str(largestDecrease), 'kWh was found between index', ])

採用された回答

David Goodmanson
David Goodmanson 2020 年 3 月 18 日
編集済み: David Goodmanson 2020 年 3 月 18 日
Hello Ireedui,
max and min find the indices as well as the values.
changeInSOE = diff(stateOfEnergy) % find all the differences
[valmax indmax] = max(changeInSOE)
[valmin indmin] = min(changeInSOE)
indmax = n says that the largest positive change of value = valmax occurred from stateOfEnergy(n) to stateOfEnergy(n+1).
indmin = m says that the largest negative change of value = valmin occurred from stateOfEnergy(m) to stateOfEnergy(m+1).
  1 件のコメント
Ireedui Ganzorig
Ireedui Ganzorig 2020 年 3 月 18 日
Thank you very much. You explained it very well. I got it. Thanks.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeAxis Labels についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by