Converting a cell array into a matrix of stipulated number of columns and rows

1 回表示 (過去 30 日間)
Consider I have a cell array containing 4 cells
Each cell containd 'n' elements
Now I want to covert it into an array of size "n*4" where element of each row is take from elements of each cell
If it has tto be more clear for eg: ist row of the matrix contains 4 elements - each element is picked from 1st element of each cell.
I have used the model
for i = 1:numel(W{1})%w is the cell
wid(i,:)=double(cellfun(@(v) v(i),W));
end
But it is taking more time in matlab.So, is there any best and simple solution for this problem which can be simulated in less time?
  2 件のコメント
Fangjun Jiang
Fangjun Jiang 2019 年 12 月 12 日
The code seems unnecessary. Please construct an example with n=2 and explain what is the input and desired output.
Alex Mcaulley
Alex Mcaulley 2019 年 12 月 12 日
Have you tried with cell2mat?

サインインしてコメントする。

採用された回答

Andrei Bobrov
Andrei Bobrov 2019 年 12 月 12 日
編集済み: Andrei Bobrov 2019 年 12 月 12 日
Let C - your cell array.
if cells sizes are the same:
out = reshape(cat(2,C{:}),[],4);
if not the same:
out = cell2mat(cellfun(@(x)x(:),C,'un',0));

その他の回答 (1 件)

meghannmarie
meghannmarie 2019 年 12 月 12 日
wid = [W{1}(:) W{2}(:) W{3}(:) W{4}(:)];

カテゴリ

Help Center および File ExchangeMatrices and Arrays についてさらに検索

製品


リリース

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by