Fit sum parameters of an overdetermined system

3 ビュー (過去 30 日間)
Marco Knobloch
Marco Knobloch 2019 年 12 月 11 日
コメント済み: Marco Knobloch 2019 年 12 月 12 日
I have a function that uses 9 inputs (cts(1) to cts (9)) and provides 1 value as result. The function needs 4 parameters (c(1) to c(4)). The code of the function is:
fun = @(c,cts) ((c(1) .* (4-c(4))) ./ (c(2)+c(3) .* 4)) *cts(1) +...
((c(1) .* (5-c(4))) ./ (c(2)+c(3) .* 5)) *cts(2)+ ...
((c(1) .* (6-c(4))) ./ (c(2)+c(3) .* 6)) *cts(3) + ...
((c(1) .* (7-c(4))) ./ (c(2)+c(3) .* 7)) *cts(4) + ...
((c(1) .* (8-c(4))) ./ (c(2)+c(3) .* 8)) *cts(5) + ...
((c(1) .* (9-c(4))) ./ (c(2)+c(3) .* 9)) *cts(6) + ...
((c(1) .* (10-c(4))) ./ (c(2)+c(3) .* 10)) *cts(7) + ...
((c(1) .* (11-c(4))) ./ (c(2)+c(3) .* 11)) *cts(8) + ...
((c(1) .* (12-c(4))) ./ (c(2)+c(3) .* 12)) *cts(9)
I have 11 measured values with each 9 inputs. From this data set I want to fit the parameters c. Is there an algorithm which I can use for this problem? I already tried lsqcurvefit, but that atempt ended with the error:
Error using lsqcurvefit (line 263)
Function value and YDATA sizes are not equal.

採用された回答

Matt J
Matt J 2019 年 12 月 11 日
編集済み: Matt J 2019 年 12 月 11 日
Your xdata should be a 9x11 matrix, your ydata should be a 1x11 vector, and the code for your function should look like this,
fun = @(c,cts) ((c(1) .* (4-c(4))) ./ (c(2)+c(3) .* 4)) *cts(1,:) +...
((c(1) .* (5-c(4))) ./ (c(2)+c(3) .* 5)) *cts(2,:)+ ...
((c(1) .* (6-c(4))) ./ (c(2)+c(3) .* 6)) *cts(3,:) + ...
((c(1) .* (7-c(4))) ./ (c(2)+c(3) .* 7)) *cts(4,:) + ...
((c(1) .* (8-c(4))) ./ (c(2)+c(3) .* 8)) *cts(5,:) + ...
((c(1) .* (9-c(4))) ./ (c(2)+c(3) .* 9)) *cts(6,:) + ...
((c(1) .* (10-c(4))) ./ (c(2)+c(3) .* 10)) *cts(7,:) + ...
((c(1) .* (11-c(4))) ./ (c(2)+c(3) .* 11)) *cts(8,:) + ...
((c(1) .* (12-c(4))) ./ (c(2)+c(3) .* 12)) *cts(9,:)
  1 件のコメント
Marco Knobloch
Marco Knobloch 2019 年 12 月 12 日
That one worked for me, thanks Matt

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeGet Started with Curve Fitting Toolbox についてさらに検索

製品


リリース

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by