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Find and count how many capital characters are in str, and then change them to lower cases USING LOOPS

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taki shi
taki shi 2019 年 10 月 15 日
回答済み: Steven Lord 2019 年 10 月 15 日
how to do this with loops i know the regular way but i want to know with loops
please if you can help then do
but dont comment if you will just make random comments and not help
please
thank you

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回答 (3 件)

Daniel M
Daniel M 2019 年 10 月 15 日
編集済み: Daniel M 2019 年 10 月 15 日
s = 'This is my String with CapiTal LETTERS in it. Let''s change them to lowercase uSiNg LoOpS.'
[caps,inds] = regexp(s,'[A-Z]','match');
numCaps = length(inds);
for n = 1:numCaps
s(inds(n)) = lower(caps{n});
end

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Rik
Rik 2019 年 10 月 15 日
You can easily do this without loops:
s = 'This is my String with CapiTal LETTERS in it. Let''s change them to lowercase uSiNg LoOpS.'
s_out=lower(s);
N_upper_case=sum(s~=s_out);
If for some strange reason you insist on doing this with loops, you can easily add some indexing:
s = 'This is my String with CapiTal LETTERS in it. Let''s change them to lowercase uSiNg LoOpS.'
s_out=s;
N_upper_case=0;
for n=1:numel(s)
s_out(n)=lower(s_out(n));
N_upper_case=N_upper_case+double(s_out(n)~=s(n));
end
If you ask me the second option is much more complex (and slower) than the first, without getting any benefits.

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Steven Lord
Steven Lord 2019 年 10 月 15 日
The isstrprop function can help you identify which characters are upper-case, which are lower-case, and which are neither. After that, your loop simply needs to see if the current letter is a different case than the next letter. Since I suspect this is a homework assignment I'm not going to give you the implementation; you should be able to complete it given these hints. If you can't, show us what you've written and ask a specific question about where you're having difficulty and we may be able to provide you with additional guidance.

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