How to sdcsd ?
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2 件のコメント
Shubham Gupta
2019 年 10 月 3 日
Not entirely sure, but is this what you want ?
V = [0,0,0,0]';
i = 2; % change i to assign 1 to the corresponding index
V(i) = 1; % generated V = [0; 2; 0; 0]
You said you 1 vector but your shows 4 different vectors with different name, what output do you want exactly?
回答 (2 件)
John D'Errico
2019 年 10 月 3 日
Don't. Instead, use arrays to store them.
n = 4;
V = eye(n);
V
V =
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
As you can see, the rows of V are exactly as you wish. You can access the i'th such vector using indexing.
V(2,:)
ans =
0 1 0 0
0 件のコメント
Steven Lord
2019 年 10 月 3 日
Rather than making a large number of variables (which will clutter your workspace and be difficult to work with) instead I recommend making one variable and accessing parts of it as needed.
V = eye(4);
for k = 1:size(V, 2)
x = V(:, k) % Equivalent of Vk
% Work with x
end
Actually, if you want to iterate over the columns of V, for has an interesting property if you specify the range over which to iterate as a matrix.
V = eye(4);
for vec = V
disp(vec)
end
vec will take on each of the columns of V in turn.
0 件のコメント
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