# Comparing 2 lists and assign a value

1 回表示 (過去 30 日間)
Saugata Bose 2019 年 9 月 9 日

Hi,
I would like to compare 2 lists. One(A) is 1D(3 x1) table and other(B) is a 2D one(3x 2). I would like to search the prsence of each element of B in A. If any element of B(B(i)) presents in A I would assign value, B(j) against a cell array of size A. I have solved it using procedural way. But to me, the complexity of the problem is a big issue when the size of A and size of B will be really big. I believe, there must have a solution which replaces this procedural way
Input:
A{10 x 1} table
=A{1 x1}='I am a boy'
=A{2 x 1}='I am good'
=A{3 x 1}='I will be best'
B{3 x 2} table
=B{1 X 1}='bad', B{1 X 2}=0.5
=B{2 X 1}='good', B{2 x 2}=0.3
=B{3 X 1}='boy', B{3 X 2}=0.3
The program will look up each element of A for the presence of any element of B. I have solved this in the following way:
s1 is the size of A
s1_ is the size of B
for i=1:s1
for j=1:s1_
if(strcmp(B.Var1(j),A(i)))
store(i)=B.Var2(j);
break;
end
end
end
But this solutiuon will no be a good one when the s1 and s1_ becomes too large. Would you have any idea how to solve it any simpler and fast way?
thanks,

サインインしてコメントする。

### 回答 (1 件)

Rik 2019 年 9 月 9 日
If you can make two arrays, you can use the ismember function, which should work well for large arrays as well.

サインインしてコメントする。

### カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by