## How to convert time format

L

### L (view profile)

さんによって質問されました 2019 年 4 月 24 日

### Walter Roberson (view profile)

さんによって コメントされました 2019 年 5 月 3 日
Walter Roberson

### Walter Roberson (view profile)

さんの 回答が採用されました
I am trying to convert the following time format (example): 1975-092T00:04:17.237 to just seconds. I have read the page https://www.mathworks.com/help/matlab/ref/datenum.html but this specific time format is giving me trouble (it is earth received time). Has anyone worked with this time format or have a simple way of converting? My data is a matrix wherein one column is time in this format. Thank you!

#### 1 件のコメント

2019 年 4 月 24 日
What is 092T00?

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## 1 件の回答

### Walter Roberson (view profile)

2019 年 4 月 24 日
採用された回答

datetime(TheString, 'InputFormat', 'uuuu-DDD''T''HH:mm:ss.SSS')
Note that this date does not include any timezone information. The 'T' does not imply anything about time zone.
It would be common for times in this format to be immediately followed by some timezone information such as ending in Z

Walter Roberson

### Walter Roberson (view profile)

2019 年 4 月 24 日
If you want the seconds to be relative to the beginning of the day the date is in, then you can get the numeric seconds as
seconds( timeofday( TheDateTimeObject ) )
However in roughly R2016a and later, datetime objects and duration objects can be used as X or Y or Z data directly -- but not if the axes has existing numeric data on it that is "hold on".
Peter Perkins

### Peter Perkins (view profile)

2019 年 5 月 3 日
" I was trying to convert this to just seconds"
L, you may also mean, "convert to seconds from some reference time." Create the reference as a datetime and subtract. The result is a duration:
> dt = datetime('1975-092T00:04:17.237', 'Format', "uuuu-DDD'T'HH:mm:ss.SSS")
dt =
datetime
1975-092T00:04:17.237
>> et = dt - datetime(1970,1,1)
et =
duration
46008:04:17
>> et.Format = 's'
et =
duration
165629057.237 sec
Walter's right that such timestamps often have a time zone suffix. Also "earth received time" makes me think that maybe you care about leap seconds, in which case you might want to set the result's timezone to 'UTCLeapSeconds':
>> et2 = dt - datetime(1970,1,1,'TimeZone','UTCLeapSeconds')
pt2 =
duration
46008:04:21
>> et2.Format = 's'
et2 =
duration
165629061.237 sec
Walter Roberson

### Walter Roberson (view profile)

2019 年 5 月 3 日
Ah, I completely missed the significance of "earth received time".

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