why does the window show me x3=27 when x3=1:2:50?
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I wrote this code ,and the c3 can be a vector ,the elements in this vector is the result of every loops,however,i found that the window show me an error ,here is my code
XX3=1:2:50
AXX3=zeros(1,length(XX3))
a3=5
b3=-3
for x3=1:2:50
y3=a3*x3^2+b3
c3(x3)=AXX3(x3)+y3
end
And here is the error
Attempted to access AXX3(27); index out of bounds
because numel(AXX3)=25.
Error in wqeqwe (line 7)
c3(x3)=AXX3(x3)+y3
I found that the x3 = 27.i wonder why? x3 is 1:2:50.there should be only 25 elements,i mean ,x3 should be as same as XX3,does anyone know where is my mistake
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回答 (1 件)
madhan ravi
2019 年 3 月 31 日
編集済み: madhan ravi
2019 年 3 月 31 日
No loop's needed:
XX3=1:2:50;
a3=5;
b3=-3;
x3=1:2:50;
y3=a3*x3.^2+b3;
AXX3=zeros(size(XX3));
c3=AXX3+y3; % if AXX3 is zero then why add it with y3 to get c3?
5 件のコメント
madhan ravi
2019 年 3 月 31 日
編集済み: madhan ravi
2019 年 3 月 31 日
% example
x = 1:25 % 25 elements
x(27) % will throw error why?
% ^^---- there exists no such element in the 27th place in x because x has only 25 elements not 27, get it?
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