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Naime
0

sort element in cell

Naime
さんによって質問されました 2019 年 2 月 20 日
最新アクティビティ Stephen Cobeldick
さんによって コメントされました 2019 年 2 月 26 日
A={[1,2,3,4,5,8,9,39],[2,3,17,18,25,26,27],[3,4,14,15,16,17,18],[4,5,6,11,12,13,14],[5,6,7,8],...
[10,11,12,13],[16,21,22,23,24],[26,28,29],[2,30],[6,31],[10,32],[19,33],[20,34],[22,35],[23,36],[25,37],[29,38]};
ref=31;
base = cellfun(@(m)any(ismember(m,ref)),A,'uni',0);
base_mes=A{find([base{:}]==1)};
include_base = cellfun(@(m)any(ismember(m,base_mes)),A,'uni',0);
result=cell(1,numel(include_base));
index_other=find([include_base{:}]==1);
for i=1:size(index_other,2)
result{i}=A{index_other(i)};
end
base_mes=[6,31], I want to find 6 and 31 in A, after this sort A according to 31 and 6.
result={[6,31],[4,5,6,11,12,13,14],[5,6,7,8],[1,2,3,4,5,8,9,39],[2,3,17,18,25,26,27],[3,4,14,15,16,17,18],[10,11,12,13],[16,21,22,23,24],[26,28,29],[2,30],[10,32],[19,33],[20,34],[22,35],[23,36],[25,37],[29,38]}

  5 件のコメント

Jos (10584)
2019 年 2 月 20 日
Apparently you question has been answered, but what if
  • there are more cells that contain 31
  • what if the cell(s) containing 31, contain more than 2 numbers
I am just curious ...
Naime
2019 年 2 月 20 日
good point. How should I fix it?
Stephen Cobeldick
2019 年 2 月 20 日
  • "there are more cells that contain 31" -> "How should I fix it?" -> only you can decide how to "fix" that, or if it needs "fixing" at all. You can tell us what you want to happen, but we cannot tell you what you want to happen in that situation.
  • "what if the cell(s) containing 31, contain more than 2 numbers" -> my answer does not assume anything about how many elements the vectors have.

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1 件の回答

Stephen Cobeldick
回答者: Stephen Cobeldick
2019 年 2 月 20 日
編集済み: Stephen Cobeldick
2019 年 2 月 20 日
 採用された回答

You can easily use logical indexing for this:
A = {[1,2,3,4,5,8,9,39],[2,3,17,18,25,26,27],[3,4,14,15,16,17,18],[4,5,6,11,12,13,14],[5,6,7,8],[10,11,12,13],[16,21,22,23,24],[26,28,29],[2,30],[6,31],[10,32],[19,33],[20,34],[22,35],[23,36],[25,37],[29,38]};
ref = 31
idr = cellfun(@(v)any(ismember(v,ref)),A);
vec = A{idr};
idv = cellfun(@(v)any(ismember(v,vec)),A);
Z = [A(idr),A(idv&~idr),A(~idv)];
Giving:
>> Z{:}
ans =
6 31
ans =
4 5 6 11 12 13 14
ans =
5 6 7 8
ans =
1 2 3 4 5 8 9 39
ans =
2 3 17 18 25 26 27
ans =
3 4 14 15 16 17 18
ans =
10 11 12 13
ans =
16 21 22 23 24
ans =
26 28 29
ans =
2 30
ans =
10 32
ans =
19 33
ans =
20 34
ans =
22 35
ans =
23 36
ans =
25 37
ans =
29 38

  4 件のコメント

Naime
2019 年 2 月 21 日
Thank you.
How can I change order inside each cell
Z{:}
ans =
6 31
ans =
4 5 6 11 12 13 14
ans =
5 6 7 8
I want to change above to this
Z{:}
ans =
31 6
ans =
6 4 5 11 12 13 14
ans =
6 5 7 8
as 31 is ref, I want to be first element in each array. Also 6 should be first element.
Stephen Cobeldick
2019 年 2 月 21 日
>> fun = @(v) sort(0-ismember(v,vec)-(v==ref));
>> [~,ids] = cellfun(fun,Z,'uni',0);
>> Z1 = cellfun(@(v,x)v(x),Z,ids,'uni',0);
>> Z1{:}
ans =
31 6
ans =
6 4 5 11 12 13 14
ans =
6 5 7 8
ans =
1 2 3 4 5 8 9 39
ans =
2 3 17 18 25 26 27
ans =
3 4 14 15 16 17 18
ans =
10 11 12 13
ans =
16 21 22 23 24
ans =
26 28 29
ans =
2 30
ans =
10 32
ans =
19 33
ans =
20 34
ans =
22 35
ans =
23 36
ans =
25 37
ans =
29 38
Stephen Cobeldick
2019 年 2 月 26 日
@Naime Ahmadi: you can probably do that using a loop or two. Try it!

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