How to convert dependent equation to independent for parallel computing (parfor)

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Abhishek Saini
Abhishek Saini 2019 年 2 月 11 日
コメント済み: Walter Roberson 2019 年 2 月 11 日
I am trying to run my code using 'parfor' but getting error due to dependent term. How to resolve that.
The code similar to below. I am getting error for third loop expression
image(: , : , i) = image(: , : , i) + image(: , : , i -1);
parfor ix = 1:nx
% expression to calculate image_c and image_d
for i = 1:nt
image(:,:,i) = image_c(:,:,i) +image_d(:,:,i);
for i=2:nt
image(:,:,i) = image(:,:,i) +image(:,:,i-1);

回答 (1 件)

Walter Roberson
Walter Roberson 2019 年 2 月 11 日
You cannot do that in parallel.
What you can do is roughly
total = zeros(size(image));
parfor i = 1 : nt
total = total + image(:,:,i);
MATLAB recognizes total as being a "reduction variable" and will take care of doing the relevant additions and locking.
  5 件のコメント
Walter Roberson
Walter Roberson 2019 年 2 月 11 日
Also it looks like
snapshot_i = snapshot_c .* snapshot_d;
with no loop needed ?


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