find a cycles in undirected graph

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NA
NA 2018 年 9 月 30 日
コメント済み: Walter Roberson 2018 年 9 月 30 日
My graph is something like this
(1,2)
(2,3)
(2,4)
(3,4)
(1,5)
(2,5)
(4,5)
(5,6)
(4,7)
(7,8)
(4,9)
(7,9)
(9,10)
(6,11)
(10,11)
(6,12)
(6,13)
(12,13)
(9,14)
(13,14)
I want to write a code that gives me this answer.
cycle_in_graph = {[1,2,5],[2,4,5],[2,3,4],[4,7,9],[6,12,13],[6,9,10,11,13,14],[4,5,6,9,10,11]};
  1 件のコメント
Walter Roberson
Walter Roberson 2018 年 9 月 30 日
There are some routines such as https://www.mathworks.com/matlabcentral/fileexchange/60814-cyclecount-a-l0 for counting cycles; perhaps they could be modified to return the cycles.

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