How can I turn a date in the format: '2018-03-25T05:15:00.000Z' in a datetime vector?
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I'm currently working with an API that gives me a timestamp like this and I can't seem to convert it in a datetime value.
Any thoughts?
Thanks in advance!
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Peter Perkins
2018 年 4 月 6 日
The short answer is
>> datetime('2018-03-25T05:15:00.000Z','InputFormat','uuuu-MM-dd''T''HH:mm:ss.SSS''Z''')
ans =
datetime
25-Mar-2018 05:15:00
The longer answer is that you've got something funny going on in the text that you posted:
>> double('2018-03-25T05:15:00.000Z')
ans =
Columns 1 through 9
50 48 49 56 45 48 51 45 50
Columns 10 through 18
8203 53 84 48 53 58 49 53 58
Columns 19 through 26
48 48 8203 46 48 48 48 90
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Thomas Nguyen
2018 年 4 月 6 日
You guys are so quick on answering people's questions :p I'm just looking around for fun assignments to tackle but everything has been solved :<<
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