( need help ) nested for loops to print the following pattern

Write a nested for loops to print the following pattern

A
BA
CBA
DCBA
EDCBA

I write my own code but the output is different any one can show me where is the mistake the code is :

for letter = 'A':'E'
     for n= 'A':letter

        fprintf(letter)
              %fprintf(n)
         end

        fprintf('\n')
     end

and the output is :

A
BB
CCC
DDDD
EEEEE

need help

[Guillaume]

A one-liner to generate that matrix:

char(toeplitz(65:69, [65, 32, 32, 32, 32]))

Obviously, not likely to be an accepted answer to this homework problem.

Answer 1

[Star Strider]

You have to count down from the present index of ‘letter’ in the loop to 1.

(It is difficult to illustrate it without providing the complete solution.)

Example —

letter = 'A':'E';
loop with index k1
   k1 = 1
   print letter(k1)
   k1 = 2
   print letter(k1), letter(k1-1) ...
   ...
end loop

Use fprintf('%s'\n', ...)|* to print the concatenated letter array.

Answer 2

[KL]

You have it almost right but I'd suggest to use for-loops for indexing through rows(lines) and columns(individual character). Also initially you can create your character vector.

For example,

 charVec = 'A':'E';

now you have all the possible characters here in this variable. Next is to use your for loops,

for letter = 1:length(charVec)
...

so first loop is for number of lines, as many lines as your number of characters.

      for n= letter:-1:1

now as you see, second loop starts from the value of first loop's iterator ( letter) and goes backwards until 1. Why? Because you want to print in reverse order, right?

Now, print it inside the loop and finish the rest.

[reem alromaihi]

when I did as you told me

 r = 'A':'E';
for letter = 1:length(r)
     for n= -1:1:letter
        fprintf('%s',n)
              %fprintf(n)
         end
        fprintf('\n')
     end

the output be like this:

[KL]

for n= -1:1:letter

this is not what I suggested. Even if you corrected it, you should not print n but the n-th element in r

[Stephen23]

@reem alromaihi: note that KL wrote "I'd suggest to use for-loops for indexing...".

Answer 3

[emad xa]

how to do

A B C D E

A B C D

A B C

A B

A