inverse laplace of s certain function
1 回表示 (過去 30 日間)
古いコメントを表示
hello. I am trying to find the inverse laplace of a function such as exp(-3s)^2/(s-4) which I know the answer will have a unit step which is the Heaviside but unfortunately it is outputting me the same what I typed;ilaplace(f).Any ideas how to get the answer?
0 件のコメント
採用された回答
Star Strider
2017 年 12 月 1 日
It works for me in R2017b:
syms s t
F = exp(-3*s)^2/(s-4);
f = ilaplace(F,s,t)
f =
heaviside(t - 6)*exp(4*t - 24)
4 件のコメント
Star Strider
2017 年 12 月 1 日
I get:
f =
exp(4*t) - 2*ilaplace(exp(3*s)/(s - 4), s, t) + ilaplace(exp(6*s)/(s - 4), s, t)
その他の回答 (0 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!