Sorting NaN

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Andy 2012 年 4 月 12 日
コメント済み: Steven Lord 2018 年 9 月 18 日
say if i have a matrix a:
a=[1 2 3;4 5 6;7 8 9;NaN NaN NaN]
i want to sort this in descending order, so i use
but the problem is, matlab puts the NaN at the top, is there a way to make it so that NaN is at the bottom? Thanks


Matt Tearle
Matt Tearle 2012 年 4 月 12 日
As long as you don't have any -Inf values in a, you could always do a quick hack:
a=[1 2 3;4 5 6;7 8 9;NaN NaN NaN]
a(isnan(a)) = -Inf;
a = sort(a,1,'descend');
a(isinf(a)) = NaN

その他の回答 (3 件)

Huw S
Huw S 2018 年 9 月 18 日
Very late to this for the original poster, but for anyone later looking how to do this....
It's in the matlab functionality.
  1 件のコメント
Steven Lord
Steven Lord 2018 年 9 月 18 日
That functionality was introduced in release R2017a. While I agree that's a good way to solve the problem now, it was not an option when the question was originally asked in 2012.


Matt Kindig
Matt Kindig 2012 年 4 月 12 日
You could do something like this:
a=[1 2 3;4 5 6;7 8 9;NaN NaN NaN];
a= sort(a,1,'descend');
in = any( isnan(a),2);
a = [ a(~in,:); a(in,:)];

Kye Taylor
Kye Taylor 2012 年 4 月 12 日
This will work
newA = a; % copy original matrix
isANanRow = any(isnan(a),2); % find rows that have a nan in them
% move those nan rows to the end
newA(end-nnz(isANanRow)+1:end,:) = a(isANanRow,:);
% sort nonnan rows and place at top of newA array
newA(1:nnz(~isANanRow),:) = sort(a(~isANanRow,:),1,'descend');


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