How to convert binary stream of length 1*524288 to decimal string of length 1*65536?

There is a need to group 8 bits in the binary stream of 1*524288 to make a decimal string..how to do this using matlab?

[Image Analyst]

What does "club" mean?

[Veera Kalyani S]

actually I meant 'group' or 'combine' the 8 bits..by the word 'club'

[Image Analyst]

Can you give a short example of how you are getting a longer decimal string from the shorter binary string, like '1101001' goes to '123456787654627838' or something?

[Veera Kalyani S]

If we have k='0000000100000010' then there is a need to get (say)h='1 2'

that is for first 8 bits...'00000001==> 1' for next 8 bits... '00000010==>2'

Answer 1

[Stephen23]

bin2dec probably does most of what you want:

 >> bin2dec(reshape('0000000100000010',8,[]).')
 ans =
     1
     2

[Veera Kalyani S]

yes..But I have binary string of length 1*524288.

k is the variable where I store that binary string.

If I code like this:

bin2dec(reshape(k(i),8,[]).')

It throws error...how to rectify this...

[Stephen23]

You seem to have put my code inside a loop, and then inside that loop you access one character of the string at a time, like this:

 k(i)

What do you expect to do with one character at a time?

My answer works perfectly for a string with size 1*524288, and it does not need any loops:

>> str = char(randi(48:49,1,524288));
>> vec = bin2dec(reshape(str,8,[]).')
vec =
 233
 164
 146
 110
 134
 162
 238
 203
etc

[Veera Kalyani S]

thank u..I got it correct