explaination about code line detection

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mohd
mohd 2012 年 3 月 6 日
hello... can everyone explain to me about codes below... thanks alot
theta = -90:89;
[R,xp] = radon(binaryImage,theta);
[R1,r_max] = max(R);
theta_max = 90;
while(theta_max > 50 || theta_max<-50)
[R2,theta_max] = max(R1);
R1(theta_max) = 0;
theta_max = theta_max - 91;
  2 件のコメント
Jan
Jan 2012 年 3 月 6 日
What do you want to be explained? Do you understand how to create a vector using "a:b"? Or are you asking about the function "radon"? Please be more specific to allow for an efficient answer.
mohd
mohd 2012 年 3 月 7 日
i want to know about the function radon in my code.

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Thomas
Thomas 2012 年 3 月 7 日
doc radon
Radon
Radon transform Syntax
R = radon(I, theta) [R,xp] = radon(...)
Description
R = radon(I, theta) returns the Radon transform R of the intensity image I for the angle theta degrees.
The Radon transform is the projection of the image intensity along a radial line oriented at a specific angle. If theta is a scalar, R is a column vector containing the Radon transform for theta degrees. If theta is a vector, R is a matrix in which each column is the Radon transform for one of the angles in theta. If you omit theta, it defaults to 0:179.
[R,xp] = radon(...) returns a vector xp containing the radial coordinates corresponding to each row of R.
The radial coordinates returned in xp are the values along the x'-axis, which is oriented at theta degrees counterclockwise from the x-axis. The origin of both axes is the center pixel of the image, which is defined as floor((size(I)+1)/2)
For example, in a 20-by-30 image, the center pixel is (10,15

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