Random and unique number generation with constraints.

1 回表示 (過去 30 日間)
Asad Abbas
Asad Abbas 2016 年 9 月 6 日
コメント済み: Asad Abbas 2016 年 9 月 7 日
Please help me. Here is given my given code where random number generation of 0 and 1 and find the unique solutions with given matrix 119*9.
pop_size = 119;
x = randi([0,1],pop_size,9);
chk = true;
while chk
[~,idx] = unique(x,'rows');
idy = setdiff(1:pop_size,idx);
x(idy,:) = randi([0,1],numel(idy),9);
chk = numel(idy)>0;
end
I want apply some constraints.
1. alternative values in c1 (first column) and c2 (second column) such as
c1 c2 c3 c4 c5 c6 c7 c8 c9
0 1 0 0 0 0 0 0 0
1 0 0 0 0 0 0 0 0
2. alternative values in c3, c4, c5 and c6 such as
c1 c2 c3 c4 c5 c6 c7 c8 c9
0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0
3. at least 1 among c7, c8 and c9
c1 c2 c3 c4 c5 c6 c7 c8 c9
0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 1 1 0
0 0 0 0 0 0 1 1 1
0 0 0 0 0 0 0 0 1
0 0 0 0 0 0 0 1 1
0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 1 1 1
Please help me How i can code these constraints.
After getting all my upper constraints my final task is to combine all as given bellow.
there are three groups
1. c1 and c2
2. c3,c4,c5 and c6
3. c7,c8 and c9
Between groups there is OR operation. as given below
c1 c2 c3 c4 c5 c6 c7 c8 c9
1 0 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0
0 0 0 0 1 0 0 0 0
0 0 0 0 0 1 0 0 0
0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 1 1 0
0 0 0 0 0 0 1 0 1
1 0 0 1 0 0 1 1 0
Something like this
If I compute all possible solutions in this way. I get 119 unique combinations
  4 件のコメント
Stephen23
Stephen23 2016 年 9 月 6 日
編集済み: Stephen23 2016 年 9 月 6 日
@Asad Abbas: your output does not seem to follow your constraints. You show that either c1 or c2 should have a 1, but most rows of your example this is not true, e.g. the third row 0 0 1 0 0 0 0 0 0. How your constraints relate to your output is not clear.
Asad Abbas
Asad Abbas 2016 年 9 月 6 日
編集済み: Asad Abbas 2016 年 9 月 6 日
@Stephen Cobeldick Sir there are three groups
1. c1 and c2
2. c3,c4,c5 and c6
3. c7,c8 and c9
Between groups there is or operation.

サインインしてコメントする。

採用された回答

John D'Errico
John D'Errico 2016 年 9 月 6 日
For example, are you asking to create a random matrix such that in each ROW, the elements in columns 1 and 2 must be either [0 1] or [1 0]?
If so, then just compute a matrix with the desired number of rows that have either of those two possibilities.
N = 119;
possibleSet = [0 1;1 0];
np = size(possibleSet,1);
M12 = possibleSet(ceil(rand(N,1)*np),:);
Next, create columns 3 through 6 separately, as desired. Combine with the first two columns.
If this is your goal, then just do it. But I have an inkling that you may have meant something entirely different, or that your real problem is far more complex.
  3 件のコメント
John D'Errico
John D'Errico 2016 年 9 月 6 日
And I explained how to generate the solution. Please read my answer. Apply that same algorithm to columns 1&2 then 3,4,5,6, then 7,8,9. If you refuse to read when someone gives you a valid answer, then how will you ever get any answer?
Asad Abbas
Asad Abbas 2016 年 9 月 7 日
Thank you so much Sir. Its working now to follow your suggestions. I have got all 119 unique solutions.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by