# How to specifically select columns in a data matrix?

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jj 2011 年 11 月 12 日

Hello guys,
I know this is a really simple question, which I can't seem to find any answers around on the internet or the help stuffs I've on Matlab.
I've uploaded a dataset with 100 data series. However, I'm trying to select only specific column, say column 77 to 83, and column 86. How do I do that in Matlab? Typically, it would be:
xdatatemp =xdata(:,77:86) - to select columns 77 to 86. But, how do I specifically select col 77 to 83, and col 86?
Many thanks.
J

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### 採用された回答

Sven 2011 年 11 月 12 日
Try:
xdatatemp = xdata(:,[77:83 86])
And you can even use "end" keywords such as:
xdatatemp = xdata(:,[77:83 86 end end:-1:end-5])
That is, of course, if you wanted columns 77 to 83, then 86, then the last column, then the last 5 columns counted backwards ;)

#### 4 件のコメント

SugerCodeCude 2018 年 10 月 9 日
Sven what if there is only one row you like to pick from? for Example a 3x3 and I want only column 3 of row 3? where do you put in the code you showed to select the row too? Never mind got it! thank you
xdatatemp = xdata(:,[77:83 86])
Gunjan Rateria 2020 年 3 月 12 日
Thank you!
Onur Ozdemir 2020 年 5 月 9 日
This worked wonderfully, thanks! I guess there's much to learn about MATLAB syntax and functions. I'm having trouble understanding several things when compared to Python and C, where doing certain tasks are are easier than doing it in MATLAB.

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### その他の回答 (2 件)

Coral del Mar Valle Rodriguez 2020 年 5 月 14 日

I have a matrix of various rows, and three columns. some of the data sets have the same number. I would like to put them together in order to graph it. how do I separate the matrix by value? for example, all the values right to the #1, etc?
1961 1 -11.4
1961 2 -12.3
1961 3 -8.2
1961 4 -8.6
1961 5 -2.4
1961 6 7.4
1961 7 14.8
1961 8 11.1
1961 9 5.9
1961 10 3.7
1961 11 -6.3
1961 12 -13.3
1962 1 -12.7
1962 2 -8.1
1962 3 -13
1962 4 -1.1
1962 5 2.8
1962 6 5.9
1962 7 12.2
1962 8 8.9
1962 9 7.2
1962 10 -0.1
1962 11 -1
1962 12 -11

#### 1 件のコメント

Rik 2020 年 8 月 20 日
Comment posted as flag by Abdul Basith Ashraf:
lookup groupsummary function. You have answered by asking a different question. Please avoid this in the future.

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prakash patel 2020 年 5 月 18 日

a=[12345; 23456; 34567; 45678]
find
i (a)(2.5)
ii colom matrix v=a(;,4)
iii matrx a
iv a(:,2:3)
v sa= a(2:3, 2:4)

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