A compact “if” statement using “or” operator

4 ビュー (過去 30 日間)
Sim
Sim 2023 年 6 月 1 日
コメント済み: Sim 2023 年 6 月 2 日
A more compact way to write the “if” statement using “or” operator, than this one?
if i == 1 || i == 2 || i == 7 || i == 8 || i == 10
% ...
end
Something similar to this statement?
if i == [1 2 7 8 10]
% ...
end

採用された回答

Dyuman Joshi
Dyuman Joshi 2023 年 6 月 1 日
編集済み: Dyuman Joshi 2023 年 6 月 1 日
Yes there is - ismember
vec = [1 2 7 8 10];
i = 4;
%Checks if elements in i are present in vec or not
ismember(i,vec)
ans = logical
0
if ismember(i,vec)
disp('if')
else
disp('else')
end
else
  7 件のコメント
Dyuman Joshi
Dyuman Joshi 2023 年 6 月 1 日
編集済み: Dyuman Joshi 2023 年 6 月 1 日
It is interesting to note that anyEq() is the fastest for first element and the slowest for the last element, and there timings of any() and ismember() are similar.
Edit - In the Overview section of the FileEx submission, Jan mentions - "Best case (first element matches): 99.99% faster for 1e6 elements (Matlab 2011b/64, MSVC 2008)"
%From the above tests done by James Tursa
n_any = 4.766502e-04;
n_is = 8.393297e-04;
n_eq = 4.046598e-06;
1-n_eq/n_any
ans = 0.9915
1-n_eq/n_is
ans = 0.9952
And it still holds.
Sim
Sim 2023 年 6 月 2 日
thanks to everyone, @Dyuman Joshi @Stephen23 @James Tursa @DGM, for your comments!

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