Sub heading in matlab table

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Davindra Usov
Davindra Usov 2023 年 1 月 16 日
コメント済み: Davindra Usov 2023 年 1 月 17 日
Hello,
I am trying to create the table shown in the image attached. So far my code generates the table with all the headings but without the 'old fruit' and 'new fruit' headings. How do I add these headings into my code?
table.Properties.VariableNames(1:4) = {'apples','oranges','strawberries','grapefruit'}
writetable(table,'fruit.csv')
thank you

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Adam Danz
Adam Danz 2023 年 1 月 16 日
編集済み: Adam Danz 2023 年 1 月 16 日
There isn't an option to arrange subheadings as described in your attached image.
However, there are several ways to rearrange the table to contain subheadings.
Option 1: nested subheaders
MATLAB R2018b or later
apples = table([3;4],[1;4],'VariableNames',{'old','new'});
oranges = table([3;4],[1;4],'VariableNames',{'old','new'});
strawberries = table([3;4],[1;4],'VariableNames',{'old','new'});
grapefruit = table([3;4],[1;4],'VariableNames',{'old','new'});
fruit = table(apples, oranges, strawberries, grapefruit)
fruit = 2×4 table
apples oranges strawberries grapefruit old new old new old new old new __________ __________ ____________ __________ 3 1 3 1 3 1 3 1 4 4 4 4 4 4 4 4
Option 2: nested subheaders version 2
MATLAB R2018b or later
old = table([3;4],[6;4],[5;3],[1;2], 'VariableNames', {'apples','ornages','strawberries', 'grapefruit'});
new = table([1;4],[1;13],[2;11],[3;3], 'VariableNames', {'apples','ornages','strawberries', 'grapefruit'});
fruit = table(old,new)
fruit = 2×2 table
old new apples ornages strawberries grapefruit apples ornages strawberries grapefruit _______________________________________________ _______________________________________________ 3 6 5 1 1 1 2 3 4 4 3 2 4 13 11 3
Option 3: Store subheaders in a table variable
MATLAB R2013b or later
Note that the use of subheadings above makes indexing difficult. Here's a recommendation that preserves the labels but allows for easier indexing:
fruit = table(["old";"old";"new";"new"], ...
[3;4;1;4],[6;4;1;13],[5;3;2;11],[1;2;3;3], ...
'VariableNames', {'age','apples','oranges','strawberries','grapefruit'})
fruit = 4×5 table
age apples oranges strawberries grapefruit _____ ______ _______ ____________ __________ "old" 3 6 5 1 "old" 4 4 3 2 "new" 1 1 2 3 "new" 4 13 11 3
  1 件のコメント
Davindra Usov
Davindra Usov 2023 年 1 月 17 日
Thank you so much!! I tried option 2 and it worked!

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