Abbreviate regexp: match a if present, else match b

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Jonas
Jonas 2022 年 11 月 9 日
コメント済み: Jonas 2022 年 11 月 14 日
dear community,
can someone abbreviate the follwing if else in a single regexp?
str1='this is } and this is }, and this is }';
str2='this is } and this is } and this is }';
if regexp(str1,'},','once')
where=regexp(str1,'},')
else
where=regexp(str1,'}')
end
where = 23
if regexp(str2,'},','once')
where=regexp(str2,'},')
else
where=regexp(str2,'}')
end
where = 1×3
9 23 38
i tried to adapt the example of the documentation, but was not able to make it work
(?(cond)expr1|expr2)
If condition cond is true, then match expr1. Otherwise, match expr2.
'Mr(s?)\..*?(?(1)her|his) \w*' matches text that includes her when the text begins with Mrs, or that includes his when the text begins with Mr.
regexp(str1,'}(,?)(?(1)},|})')
ans = []
best regards
Jonas

採用された回答

Stephen23
Stephen23 2022 年 11 月 14 日
編集済み: Stephen23 2022 年 11 月 14 日
It is possible to combine them, but it will be fiddly and not very efficient because it requires in some way checking the entire text for the existence of the specified substring when performing every single match. Here is one approach that combines a conditional operator with a dynamic command:
st1 = 'this is } and this is }, and this is }';
st2 = 'this is } and this is } and this is }';
rgx = '\}(?(?@contains([$`,$&,$''],''},'')),)';
regexp(st1,rgx)
ans = 23
regexp(st2,rgx)
ans = 1×3
9 23 38
Broken down:
% '\}(?(?@contains([$`,$&,$''],''},'')),)';
% \} literal curly brace
% (?( ),) conditional match comma
% ?@contains( , ) dynamic check text content:
% [$`,$&,$''] entire input text
% ''},'' literal curly-brace & comma
You could probably do something similar with lookarounds. But as noted, the condition command will be called again and again with each match... this is rather inefficient, because your condition does not change. I do not see an obvious way to avoid this. A more efficient approach (if you are able to relax your requirements) is probably to check that condition once before calling regexp:
rgx = '\}(?(?@tmp),)';
tmp = contains(st1,'},');
regexp(st1,rgx)
ans = 23
tmp = contains(st2,'},');
regexp(st2,rgx)
ans = 1×3
9 23 38
  1 件のコメント
Jonas
Jonas 2022 年 11 月 14 日
it seems like i misunderstood the concept of condition in this case since the condition is checked in each case (like you said). thanks for your code!

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