Determine the magic sum from a magic square
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Determine for a magic square of order n, the magic sum m. For example m=15 for a magic square of order 3.
For this problem I wrote:
m = sum(n)
This gave me 15 15 15. Why is this not correct?
I then tried
m = sum(n(1, :))
This gave me 15. Why is this not correct?
I don't understand why my answer is not accepted. This is for Cody Problem 1087: Magic is simple (for beginners).
1 件のコメント
David Goodmanson
2022 年 9 月 22 日
Hi Farook,
It looks like you are given the size of the magic square, but not the magic square itself. So if all you are given is that the magic square is 3x3, how do you obtain 15 from n=3?
採用された回答
Davide Masiello
2022 年 9 月 22 日
編集済み: Davide Masiello
2022 年 9 月 22 日
I think you are inputting the magic square itself to your function, rather than its order.
I believe the relation between a magic square order (n) and the magic sum (S) is
So your function should be
function out = magic_sum(n)
out = n*(n^2+1)/2
end
2 件のコメント
Nathan Hardenberg
2023 年 7 月 25 日
While the formula is a valid solution I think the intended way is to sum up one colum or row, since all rows/colums and diagonals do sum up to the same number:
mag_sqr = magic(3)
sol1 = sum(mag_sqr(:,1)) % sum up first colum
sol2 = sum(mag_sqr(1,:)) % sum up first row
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