Is there any other function faster than sum(A,2) to get the sum of all rows?

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Nadatimuj
Nadatimuj 2022 年 6 月 26 日
コメント済み: Walter Roberson 2022 年 6 月 27 日
a=zeros(6750);
h=zeros(6750,1);
tic;k=h-sum(a,2); toc
Elapsed time is 0.041132 seconds.
Is there any faster way than to use sum(A,2) to get the sums of the rows of a matrix? sum(A,2) seems to be slow for large matrices.
  4 件のコメント
Image Analyst
Image Analyst 2022 年 6 月 27 日
The Parallel Processing Toolbox is an add-on toolbox. You can ask for a free trial of it and see if the Parallel Processing Toolbox helps. I know some functions recognize if you have that toolbox and start parallel processes going on multiple CPU cores on your computer automatically.
Walter Roberson
Walter Roberson 2022 年 6 月 27 日
For sufficiently large matrices, addition is automatically handled by high performance parallel libraries. Using parfor or parfeval() will not improve performance compared to the automatic multi-core work that is done.

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回答 (2 件)

Walter Roberson
Walter Roberson 2022 年 6 月 26 日
Switching to columns can improve performance as it allows better use of hardware cache.
  2 件のコメント
Nadatimuj
Nadatimuj 2022 年 6 月 26 日
Thanks for the suggestion. Did you mean this? Doesn't look like to save too much time...
a=zeros(6750);
h=zeros(1,6750);
tic;k=h-sum(a,1); toc
Elapsed time is 0.033019 seconds.
Walter Roberson
Walter Roberson 2022 年 6 月 27 日
When I test on my system, the sum(a,1) version is 5 to 6 times faster than the sum(a,2) version

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MJFcoNaN
MJFcoNaN 2022 年 6 月 26 日
In general, the native functions are optimized sufficiently.
In certain cases, there may be some better way but in other parts of code. For example,
a=sparse(zeros(6750));
h=sparse(zeros(6750,1));
tic;k=h-sum(a,2); toc
Elapsed time is 0.003234 seconds.
  1 件のコメント
Nadatimuj
Nadatimuj 2022 年 6 月 26 日
Thanks, yes that's a good idea. However, originally I didn't use the sparse notation, I will check if using sparse will impact other parts of the code. Otherwise sparse conversion just here can take some time.

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