Create cell array of column indices of a specific string

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Davindra Usov 2022 年 6 月 21 日
コメント済み: Voss 2022 年 6 月 22 日
Hi,
I have a 5x1 cell array ,g, where each cell is 40x50. I want to find the column indices of the string 'Latitude' in each of the cells in the cell array. I know there is 7 occurences of this string in each of the cells but I want the code to tell me that. My desired output is a new cell array where each cell contains the column indices of this string (so it will end up being a 5x1 cell array where each cell contains the 7 column indices). I tried this:
ind=find(~cellfun('Latitudes', g));
but it won't work. Any suggestions would be much appreciated
Thank you

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採用された回答

Voss 2022 年 6 月 22 日
% make cell array g
g = repmat({repmat({''},40,50)},5,1);
% put 7 random 'Latitude's in each cell
for ii = 1:5
g{ii}(randi(2000,7,1)) = {'Latitude'};
end
% get the column index of each instance of 'Latitude'
cidx = cellfun(@get_latitude_columns,g,'UniformOutput',false)
cidx = 5×1 cell array
{7×1 double} {7×1 double} {7×1 double} {7×1 double} {7×1 double}
% put them together in a matrix, if you prefer
% (5x7 or 7x5, whatever makes sense to you)
cidx = [cidx{:}].'
cidx = 5×7
2 3 19 20 30 48 50 8 8 10 11 25 36 46 10 28 29 29 31 32 42 14 16 17 22 34 43 45 2 19 21 25 36 39 50
function idx = get_latitude_columns(s)
[~,idx] = find(strcmp(s,'Latitude'));
end
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Voss 2022 年 6 月 22 日
You're welcome!

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