# how to compare two values that are repeated in two vectors?

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giancarlo maldonado cardenas 2022 年 6 月 2 日
Hello everyone, I'm new to matlab, I wanted to know how I can compare 2 values that are repeated between two vectors, I'll explain myself better, for example I have these two vectors.
A = [10 56 34 11 34 ];
B = [10 56 34 11 ];
Now I need to compare element by element, I mean...
vector B = [(10) 56 34 11]; element 10 is repeated in vector A? No then it is assigned the number 1.
vector B = [10 (56) 34 11 ]; element 56 is repeated in vector A? No then it is assigned the number 1.
vector B = [10 56 (34) 11 ]; element 34 is repeated in vector A? Yes! then it is assigned the number 0.
vector B = [10 56 34 (11) ]; element 34 is repeated in vector A? Yes! then it is assigned the number 1.
the result has to be an array, equal to this.
result= [10 1
56 1
34 0
11 1]
any help will be very helpful.
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Image Analyst 2022 年 6 月 2 日

What if the numbers are not in the same index in the two vectors, like
A = [10 56 34 11 34 ];
B = [11 10 56 34 5 ];
are the 10, 56, and 34 repeated in B? What's your definition of repeated?
And is this your homework (sounds like it)?
giancarlo maldonado cardenas 2022 年 6 月 2 日
Maybe I expressed myself in the wrong way!
I meant for example in the vector B = [10 56 (34) 11 ]; in vector A element 34 is repeated twice? Yes! then it is assigned the number 0.
then all the other values of B are not repeated twice in A so it is assigned the label 1, the only value of B repeated twice in A is the value 34, therefore it is assigned the label 0.

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### 採用された回答

Voss 2022 年 6 月 2 日

A = [10 56 34 11 34 ];
B = [10 56 34 11 ];
result = [B.' sum(A==B.',2)<=1]
result = 4×2
10 1 56 1 34 0 11 1
Breaking that expression down:
A==B.' % compare each element of A to every element of B
ans = 4×5 logical array
1 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 1 0
sum(A==B.',2) % sum each row to get the number of occurrences in A of each element of B
ans = 4×1
1 1 2 1
sum(A==B.',2)<=1 % if the number of occurrences is NOT 2 or more, that's a 1 in the result, otherwise a 0
ans = 4×1 logical array
1 1 0 1
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giancarlo maldonado cardenas 2022 年 6 月 5 日

is there a way to do it with a for loop, and not altogether?
I have to compare each element of vector B and traverse vector A in search of if that element is repeated twice, then an IF condition, if label 0 is repeated, if label 1 is not repeated, but this label can also be 0 with a probability of 10%. this is my code when comparing repeated elements in a single vector.
can u help me?
Voss 2022 年 6 月 5 日

I don't understand what you mean by "if label 0 is repeated, if label 1 is not repeated, but this label can also be 0 with a probability of 10%", but here is how you can perform the task from the original question using a for loop:
A = [10 56 34 11 34 ];
B = [10 56 34 11 ];
result = [B.' zeros(numel(B),1)];
for ii = 1:numel(B)
result(ii,2) = nnz(A==B(ii))<=1;
end
disp(result);
10 1 56 1 34 0 11 1

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