Where can I find Fcn block in simulink in matlab R2022a?

In previous realeses of Matlab there was the "Fcn" block when I used Simulink, How can I avoid this problem in Matlab R2022a?

Answer 1

[Steven Lord]

Which of the blocks in the User-Defined Functions library do you want to use?

I'm guessing you want either MATLAB Function or Interpreted MATLAB Function.

[Adolfo Marro]

No, I said that in previous releases there was simply the block "Fcn" to create functions with u(1) and u(2) in it. In R2022a there is no more this block, so I ask you: How can I put a simple expression in Simulink such as "sin(u1)" without that "Fcn" block

[Sam Chak]

Hi @Adolfo Marro

You can use the Interpreted MATLAB Function to achieve basically the same thing for simple inputs and static nonlinearity.

https://www.mathworks.com/help/simulink/slref/interpretedmatlabfunction.html

Else, you can find older version of Simulink file that contains the Fcn block. Then, copy the block to your Simulink model in R2022a.

[Les Beckham]

I think it has been renamed "Math Function". Documentation is here.

Other common math operations (such as sin) are documented here.

[Sam Chak]

@Les Beckham, the Math function block has been there in the Math Operations library. @Adolfo Marro is looking for the Fcn block that was available in previous Simulink versions (I think in pre-R2020 releases).

The Fcn block comes in handy for user who wishes to quickly enter a relatively simple equation such as:

u(1) + sin(u(2))*tan(u(3)) + cos(u(2))*tan(u(3))

without pulling multiple trigonometric function blocks, product blocks and summation blocks.

[Les Beckham]

@Sam Chak, oh, yes, I remember that block now. It has been a while since I worked with Simulink. As you said, the Interpreted Matlab Function block appears to be the replacement.

[Andreas]

@Sam Chak But the interpreted matlab function is set to be removed in the future as well.

"The Fcn block comes in handy for user who wishes to quickly enter a relatively simple equation such as:

u(1) + sin(u(2))*tan(u(3)) + cos(u(2))*tan(u(3))"

Exactly. Any better way to achive this?

Answer 2

[Harun GIRGIN]

Thank you all and your answers. These helped a lot.

Answer 3

[Sam Chak]

Hi @Adolfo Marro, @Andreas, @Harun GIRGIN

You can try if the following blocks from the older release still work in your system.