Matlab: Convert [2x1 sym] to a numerical value

Below is my code and I wish to solve for A, B, C and D. How do i change the code to get numerical values for A, B, C and D? Instead of [2x1 sym].

syms A B C D
E = (89*50*sind(170))+(92.3*A*sind(C))+(83.3*B*sind(D))==0;
F = (89*50*cosd(170))+(92.3*A*cosd(C))+(83.3*B*cosd(D))==0;
G = (89*sind(170)) + (92.3*sind(C)) + (83.3*sind(D))==0;
H = 68.4 + (89*cosd(170)) + (92.3*cosd(C)) + (83.3*cosd(D))==0;

s = solve([E,F,G,H],[A,B,C,D])

When the code is run:

RV1_SDbalancing

s = 

  struct with fields:

    A: [2×1 sym]
    B: [2×1 sym]
    C: [2×1 sym]
    D: [2×1 sym]

Answer 1

[Stephen23]

syms A B C D
E = (89*50*sind(170))+(92.3*A*sind(C))+(83.3*B*sind(D))==0;
F = (89*50*cosd(170))+(92.3*A*cosd(C))+(83.3*B*cosd(D))==0;
G = (89*sind(170)) + (92.3*sind(C)) + (83.3*sind(D))==0;
H = 68.4 + (89*cosd(170)) + (92.3*cosd(C)) + (83.3*cosd(D))==0;

s = solve([E,F,G,H],[A,B,C,D])

s = struct with fields:
    A: [2×1 sym]
    B: [2×1 sym]
    C: [2×1 sym]
    D: [2×1 sym]

double(s.A)

ans = 2×1

179.1120 136.9546

double(s.B)

ans = 2×1

205.5649 110.5017