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How to draw a pulse train

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Sadiq Akbar
Sadiq Akbar 2022 年 3 月 15 日
コメント済み: Scott MacKenzie 2022 年 3 月 17 日
I want to draw a pulse train in Matlab like the one shown blue in attached picture. The duration of each pulse is Tp and there are M=199 zeros in between two consective pulses. The PRI of the pulse train is 200Tp. Then I want to decompose each pulse into 7 small pulses of amplitude +1 and -1 (i.e., 1Tp=7Tc where Tc=28ns is the duration of small pulse) like shown white in the attached picture.
  1 件のコメント
Sadiq Akbar
Sadiq Akbar 2022 年 3 月 16 日
I write a code that draws a square train. The code is as below:
clear all
clc
fy=100;
wy=2*pi*fy;
duy=0.02;
fs=20000;
dt=1/fs;
t=-(duy-dt):dt:(duy-dt);
A=1.5;
y=A*square(wy*t);
plot(t,y,'k')
axis([-duy duy -2.5 2.5])
xlabel('Seconds')
title('Square signal')
Now I want to replace each -ve pulse with M=199 zeros. Can anyboy help me how to do that?

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回答 (1 件)

Scott MacKenzie
Scott MacKenzie 2022 年 3 月 16 日
編集済み: Scott MacKenzie 2022 年 3 月 17 日
It seems you want to replace the negative portion of the pulse with zeros. Like this, perhaps:
fy=100;
wy=2*pi*fy;
duy=0.02;
fs=20000;
dt=1/fs;
t=-(duy-dt):dt:(duy-dt);
A=1.5;
y=A*square(wy*t);
subplot(1,2,1);
plot(t,y,'k')
axis([-duy duy -2.5 2.5])
xlabel('Seconds')
title('Square signal')
subplot(1,2,2);
y(y<0)=0;
plot(t,y,'k')
axis([-duy duy -2.5 2.5])
xlabel('Seconds')
title('Square signal')
  6 件のコメント
Sadiq Akbar
Sadiq Akbar 2022 年 3 月 17 日
ok Scott MacKenzie thank you very much. At least you tried your best to help me out. So thank you very much for your try and your good step for my help.
Scott MacKenzie
Scott MacKenzie 2022 年 3 月 17 日
You're welcome. Good luck.

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