Can somebody solve this question. I've been trying for 2 hours straight. Didn't get it yet

2 ビュー (過去 30 日間)
Yuvraj Pai Khot
Yuvraj Pai Khot 2022 年 1 月 11 日
編集済み: Matt J 2022 年 1 月 11 日
Find the volume of the solid generated by revolving about the x-axis the region bounded by the curve y = sqrt(x) , the x-axis, and the line y= x-2.
  1 件のコメント
Matt J
Matt J 2022 年 1 月 11 日
Yes, but it's your homework. Are you not worried your instructor will catch you posting it? You know you are not allowed to delete this, right?

サインインしてコメントする。

サインインしてこの質問に回答する。

回答 (1 件)

Matt J
Matt J 2022 年 1 月 11 日
編集済み: Matt J 2022 年 1 月 11 日
Ran in:
Hint: Notice that the volume is the difference of two simpler volumes V1-V2, where V1 is the volume of revolution of sqrt(x) on the interval [0,4] and V2 is the volume of the cone swept out by the line x-2 on the interval [2,4].
x=linspace(0,5);
plot(x,sqrt(x),x, max(x-2,0) )

カテゴリ

Help Center および File Exchange で Surface and Mesh Plots についてさらに検索

タグ

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by