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why does my program terminate

1 回表示 (過去 30 日間)
Pat
Pat 2011 年 9 月 16 日
閉鎖済み: MATLAB Answer Bot 2021 年 8 月 20 日
Hiwhile i run this program my programhangs on ,dont now why,can anyone help me please
Fuzzification
[nu da]=xlsread('lymphoma dataset.xls')
cl=xlsread('class.xls');
for i=1:size(da,1)
for j=2:size(da,2)
if(j<size(da,2))
% x=str2num(da{i,j});
% if(isempty(x))
% x=0;
% end
else
c=unique(da(:,end));
% for i1=1:length(c)
% if(strcmp(c{i1},da{i,j}))
% x=i1;
% end
% end
% end
data(i,j-1)=x;
end
end
data1=data;
% data=data(1:300,:);
% cl=cl(1:150,:);
% data=nu;
disp('Dataset')
disp(data)
data=knnimpute(da)
[in claq]=kmeans(data,4);
for i=1:size(da,2)
d=data(:,i);
Emin=min(d);
Emax=max(d);
d1=sort(d,'ascend');
s=size(d,1)/3;
pj1=d(1:s,:);
pj2=d(s+1:end,:);
cl=in;
cla1=cl(1:s,:);
cla2=cl(s+1:end,:);
nc=10;
de=1;
k1 = mat2cell(pj1, nc*ones(1, (s/nc)),1);
k2 = mat2cell(pj2, nc*ones(1, (size(pj2,1)/nc)),1);
Rk1=(2*1)/length(pj1);
Rk2=(2*2)/length(pj2);
%class
figure('visible','off')
h = cdfplot(cla1);
y = get(h,'YData');
f1=length(y);
y = unique(y);
h1 = cdfplot(cla2);
y1 = get(h1,'YData');
f2=length(y1);
y1 = unique(y1);
low1=y(2);
low2=y1(2);
cf1=y(2)-y(1);
cf2=y1(2)-y1(1);
Pj1=low1+((Rk1-cf1)/f1)*de;
Pj2=low2+((Rk2-cf2)/f2)*de;
Aj1(i)=(Emin+ Pj1)/2;
Aj2(i) =(Pj1 + Pj2 )/2;
Aj3(i)= (Pj2 + Emax )/2;
end
  3 件のコメント
Andreas Goser
Andreas Goser 2011 年 9 月 16 日
And also be specific about "terminate"
Jan
Jan 2011 年 9 月 18 日
@Pat: You've asked 41 questions now. I'd expect that you've learned how to ask good questions and how to format your code. If you interested in getting answers, make your question easy to understand and to read would be a good idea.

回答 (1 件)

Vineeth Kartha
Vineeth Kartha 2016 年 5 月 3 日
Hi,
Insert breakpoints at each xlsread command and see if it is one of the xlsread that is causing the problem.
Regards Vineeth
  1 件のコメント
Jan
Jan 2016 年 5 月 3 日
@Vineeth Kartha: Did you see that the question is 5.5 years old and that the OP did not reply to questions for clarifications? I assume he was not interested in a solution.

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